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Hello, In my laravel5.5/vuejs2.5 application I define resource in routes/web.php filter as :
Route::resource('tasks/{filter}', 'TasksController', ['except' => ['create', 'edit']])->middleware('WorkTextString');
And in app/Http/Controllers/TasksController.php I have default filter :
<?php
namespace App\Http\Controllers;
use Auth;
...
class TasksController extends MyAppController
{
use funcsTrait;
public function index($filter= '')
{
But I got error:
Route pattern "/admin/tasks/{filter}/{{filter}}" cannot reference variable name "filter" more than once.
even when I do not use this route...
Why this error and how to fix it?
Thanks!
If you want to add custom route to Resource collection just add before that route separately like this
Route::get('tasks/{filter}', 'TasksController@tasksFilter');
Route::resource('tasks', 'TasksController', ['except' => ['create', 'edit']])->middleware('WorkTextString');
Check this https://laravel.com/docs/5.5/controllers#resource-controllers available resource routes by default. If any custom route can be added before the resource route.
Thank you for your advice, it looks good, but when I try to get 1 item like:
tasks/id
looks like it is confused with
tasks/{filter}
Can you advice simple/effective way to deal it ?
You cannot have two dynamic routes in the same syntax for example
Route::get('tasks/{filter}'...
Route::get('tasks/{id}'...
You must change either one of them, since tasks/{id} is resource route I suggest to change the filter route bit like
Route::get('tasks/filter/{filter}', 'TasksController@tasksFilter');
Route::resource('tasks', 'TasksController', ['except' => ['create', 'edit']])->middleware('WorkTextString');
Its probably better that your filters are query strings - and as such don't need to be passed to the index method signature.
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