Need help getting a variable to work properly.

I'm performing a post to a third party API. The post is successful in the below example when the URL is hard coded.

$content = '{
  "url": "https://www.test.com",
  "type": "URL_UPDATED"
}';

ddd($content);

yields this

"""
{
  "url": "https://www.test.com",
  "type": "URL_UPDATED"
}
"""

However, I need the URL to be a variable. The URL I need to use is being captured in a form and being passed through an HTTP Request. I confirmed it's coming across correctly.

    $content = '{
  "url": "$request->id_url",
  "type": "URL_UPDATED"
}';

ddd($content);

yields this

"""
{
  "url": "$request->id_url",
  "type": "URL_UPDATED"
}
"""

So, now I know that my variable isn't being recognized - and I know it has something to do with the single quote wrapper and/or the double quote requirement around the URL.

Have researched for quite a while and tried different methods for escaping and refactoring $content but I can't figure it out.

chiefguru

3 years ago

Level 8

@gerardw85 try a simple json_encode

$content = json_encode(['url' => $request->id_url, 'type' => 'URL_UPDATED']);

1 like

Snapey

3 years ago

Best Answer

Level 122

use double quotes or concatenation, or sprintf

$content = "{
  \"url\": \"{$request->id_url}\",
  \"type\": \"URL_UPDATED\"
}";

//or

$content = '{
  "url": "' . $request->id_url . '",
  "type": "URL_UPDATED"
}';

//or

$content = sprintf('{
  "url": "%s",
  "type": "URL_UPDATED"
}', $request->id_url);

1 like

gerardw85

3 years ago

Level 2

@Snapey thank you - used your second suggestion and it worked.

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