PHP general question - 2

Yeah ::class will return the full path of the class as a string. So it's not giving back the reference of the class

The special ::class constant is available as of PHP 5.5.0, and allows for fully qualified class name resolution at compile time, this is useful for namespaced classes:

You can create a class using the following actions

$instance = new SomeModel();
$instance = new SomeModel;

$class = SomeModel::class;
$instance = new $class();

@BOBBYBOUWMANN - So basically I am doing

$class = SomeModel::class;
$instance = new $class();

So I guess you are saying that:

 public static function __callStatic($method, $params)
    {
        $instance = SomeModel::class;
        $c = new $instance;
        return $c->$method(...array_values($params));
    }

Is doing it correct? Thanks for reply.

But no matter, in the callstatic I have, you will always need the new keyword, is that correct.

I primarily use laravel now, but an old custom framework I keep updated, even php 7.3 ready now. Just modernizing some.

What's crazy, I can read this stuff in the php manual, ---nothing.

But when I study laravels api and vendor folder, and see how Taylor used the splat operator, it makes more sense. Meaning like:

return $c->$method(...array_values($params));

The three dots is the splat operator for others reading who may be new to it, also cronix helped me with the splat in another post.

That looks correct to me! Glad I could help ;)