I am referencing this episode: https://laracasts.com/series/laravel-6-from-scratch/episodes/28?autoplay=true
In that episode, Jeffrey creates the following function in the Article model:
public function path() {
return route('article.show', $this);
}
Now, this works just fine and returns the following url structure: www.mydomain.com/article/{id}
However, I would like to tweak it a bit. I want my url structure to be like this: www.mydomain.com/article/{id}/{slug}
So, what I want to know is how do I have to modify the path function in order to return this url structure - i.e., the one with both the id and the slug?
since the whole model is passed to the route helper, it will look at the placeholders in the Route and fill in any parameters required.
So in web.php you will have something like
Route::get('article/{id}', 'ArticleController@show');
It should be enough to just add the slug
Route::get('article/{id}/{slug}', 'ArticleController@show');
I tried that, but I still get an error when testing it out in tinker. Here is my web.php file looks like:
Route::get('articles/{article}/{slug}', 'ArticleController@show')->name('articles.show');
And here is my path function:
public function path() {
return route('articles.show', $this);
}
I then fire up tinker and run that path function and get the following error:
Illuminate/Routing/Exceptions/UrlGenerationException with message 'Missing required parameters for [Route: articles.show] [URI: articles/{article}/{slug}].'
Any idea why?
You don't have a model column called article. either change it to {id} or be explicit in the route helper
public function path() {
return route('articles.show', ['article' => $this->id, 'slug' => $this->slug]);
}
Thanks.
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