How to pass current input value as URL parameter?

I am not sure how to search for information about the solution I am trying to make so I apologize if this is a replicate of another post or if this is not the correct forum (I was also thinking to place it in Elocuent)

I have a simple form in my index.blade.php

<form method="POST" action="{{ route('articles.index', ['search' => $search]) }}">
@method('PUT')
@csrf
    <div class="field">
        <label class="label blog-sidebar-label" for="search">
            <input class="search-field" type="search" name="search" id="search" placeholder="Buscar..." value="{{ $search }}">
        </label>
    </div>
</form>

I want to pass the value of the input "search" as a parameter of the URL

The route articles.index is "/blog" so what I want to have as result is "MyURL/blog?search=ValueOfSearch"

With the current code in the form, I have managed to show the parameter ?search= after I send the form but it always takes the previous value of $search

my controller looks like this

public function index()
    {
        $search = '';
        if (request('search'))
        {
            $articles = Article::where('title', 'LIKE', '%'.request('search').'%')->paginate(20);
            $search = request('search');
        }
        elseif (request('tag'))
        {
            $articles = Tag::where('name', request('tag'))->firstOrFail()->articles()->paginate(20);
        }
        else {
	        $articles = Article::latest()->paginate(20);
        }
        $tags = Tag::orderBy('name')->get();

        //return dd($articles);
        return view('articles.index', ['articles' => $articles, 'tags' => $tags, 'search' => $search]);
    }

With this the first time I search something I get the URL => MyURL/blog?=

The second time I search something I get the URL => MyURL/blog?=PreviousSearchString

Is there any way to pass the current value from the request directly as an URL parameter?

Thank you in advance for your support

Have a good day