How to make param dynamic in paginate function?

@Sinnbeck sorry, not sure that I fully understand. What should I put in that variable? Some sort of counter?

@Yorkata I dont understand what you mean. You pass these when you actually use it.. You cannot overwrite the defaults globally if that what you mean.

@Sinnbeck If I add it like that:

->paginate(1, ['*'], 'page', $currentPage);

It returns an error - that the variable is undefined. And that's what confuses me

@Yorkata Well what do you want to pass to it? Why do you want to override the page in the first place?

@Sinnbeck The page number. Since pages are not changing by default. When I pass a number let's say 2 it will be only on the second page so I thought if I can make it dynamic the pages will change with no problem

@Yorkata Laravel will automatically grab it from the url, if you use it as it is supposed to be used. When you click on page 2 in pagination links, it will add &page=2 to the url, which will make laravel show page 2. If this does not work, you might want to show some code, so we can help fixing it

@Sinnbeck When I click on page 2 or any of the other pages the URL changes (?page=1, ?page=2, ?page=6) but the page itself does not. Displays the same results no matter whats in the URL

@Yorkata So maybe a bad query. You still havent shown any code?

@Sinnbeck Yes, sorry That's whats inside my controller

public function index()
    {   
      $competitions = Competition::orderby('id','DESC')->paginate($perPage = 1, $columns = ['*'], $pageName = 'competition');    
        return view('competition.index', compact('competitions'));   
    }

I've been stuck with this for so long

EDIT: In view:

 {{ $competitions->links() }}