How to make listing with pagination with pretty url

Hello, In laravel 8 I try to make listing with pagination with url like

http://site.com/admin/categories/page/3

and looking at branch https://stackoverflow.com/questions/20974404/laravel-pagination-pretty-url I tried to remade it for laravel 8 , replacing method getCurrentPage with ->path() method :

        $links = $categories->links();
        $patterns = array();
        $patterns[] = '/'.$categories->path().'\?page=/';
        $replacements = array();
        $replacements[] = '';
        echo '<pre>$patterns::'.print_r($patterns,true).'</pre>';
        echo '<pre>$replacements::'.print_r($replacements,true).'</pre>';
        // echo '<pre>$links::'.print_r($links,true).'</pre>';
         echo  preg_replace($patterns, $replacements, $links);

I see output :

$patterns::Array
(
    [0] => //admin/categories\?page=/
)
$replacements::Array
(
    [0] => 
)

But I got error :

preg_replace(): Unknown modifier 'a' (View: .../admin/categories/index.blade.php)

I tried to wrap like :

  $patterns[] = '/'.preg_quote( $categories->path() ).'\?page=/';

Or

  $patterns[] = '/'.addslashes( $categories->path() ).'\?page=/';

but got the same error anyway.

Which way is valid?

Thanks!