I am rebuilding portions of a website into Laravel 5.2. I would like to leverage an existing translation database/architecture from the old site (42 languages in 50+ countries). Time constraints do not allow me to overhaul the translation system.
Part of this architecture depends on getting a filename for the translation. This is because the same English text can be translated differently in different parts of the site depending on the country due to legal reasons.
I would like to do something like:
@include('translation', ['page' => resource_path('views/path/to/pre-compiled/view.blade.php')])
Only I would like to generate the page location instead of hard coding it.
I can't seem to find a reliable way to get the pre-compiled view's path.
I cant use ['page' => __DIR__] because that would point to the compiled and cached view file.
I can't use $_SERVER['SCRIPT_NAME'] that will always be the same like 'public/index.php'.
I can't use the URL or $_SERVER['PHP_SELF'] as the generated page from the URL is made up of many different partials. And doing so will make the translation database have way too many duplicates.
I tried using ['page' => $this->getCompiler()->getPath()] but that only returns the filename when it needs to be compiled, when it is just loading from the cache this returns blank. While I could disable caching site wide it is not a good solution.
I fixed my problem I extended the Blade compiler as so:
Blade::extend(function ($view, $compiler) {
$path = $compiler->getPath();
if (strpos($path, 'views/translation.blade.php') !== false) {
return $view;
}
$app_path = app_path();
$path = str_replace($app_path, '', $path);
$view = "@include('translation', ['domain' => '$path'])\n$view";
return $view;
});
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