Level 9
I have tried with Route::currentRouteName() but it is getting the entire view like this users.index/id.create which is invalid. I only need the users/ bit.
Thanks.
May 10, 2020
8
Level 9
Get current route dinamically
I want to be able to do something like href="{{ route }}/{{ id }}/create" where {{ route }} is getting the current route.
I am generating a "add new" button on different views. Each of these views have a controller where I have the create method. I managed to get the id dynamically but I want to do the same thing for the route. Because If I hard code the path like /users/{{ id }}/create/ since this is dynamically generated on multiple views, I want to be able to point to the correct path {{ route }} instead of /users.
Hope it makes sense.
Thanks.
Level 88
You can just get the current path or route name using the following commands
Request::current();
Documentation: https://laravel.com/docs/6.x/routing#accessing-the-current-route
Level 88
I think this should work for you as well {{ url()->current() . '/' . $id . '/create' }}
1 like
Level 9
The problem with url()->current() is that Is getting the full URL so the link becomes http://my-url/id/create so when I click on the link in the browser I have the URL twice.
Level 9
Problem solved:
{{ \Request::segment(1) . '/' . $id . '/create' }}
Level 88
What happens when you're URL looks like /users/images/{id}/create? This doesn't look like a solid solution, but it's up to you.
Level 9
I am only using these tables on the routes where I have the /{{ route }}/{{ id }}/create method in the controller. (customers, vehicles, jobs etc.)
But, if needed I can also check if route name == somethindWhereTheUrlStructureIsDifferent then I modify the link for the button...
Level 9
I still have to CONCAT FirstName and LastName for the search query... I didn't fixed that last time... What I did was to CONCAT and display the columns as one but when I make the search is not working...
https://laracasts.com/discuss/channels/code-review/livewire-tables
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