Level 12
What do you mean by "dynamic pagination"? AJAX based pagination or what?
Jun 16, 2022
6
Level 7
Dynamic Pagination
Hey there!
I wonder, how would you go about making the pagintion data dynamic, based on some parameters?
So I have a layout that has a filtering menu and pagination, the only thing that's different is the content in between.
So my question is, how do you make this dynamic:
{{ $houses->links() }}
{{ $flats->links() }}
The variable would need to be dynamic.
In my filtering menu I did something like this: {{Request::getPathInfo()}}?pageName={{$url }}"> which sees to work so far for all pages.
Level 7
So this variable would be dynamic: houses and flats,normal blade file.
{{ $houses->links() }}
{{ $flats->links() }}
The pages share the same layout basically.
Worst case scenario can go with a switch or if/else statement to check what page it is and write the URL manually.
Level 12
@aurelianspodarec I really can't understand you. You want 1 paginator for both variables?
Level 7
@Laralex I want one layout file that includes the filtering and pagination.
The data is different though.
layout
<x-layouts.main>
<x-container>
<x-inspiration.filter.index />
</x-container>
@yield('content')
<div>
{{ $Route::current()->links() }}
</div>
</x-layouts.main>
Basically this, but this part is wrong $Route::current()->links()
Level 122
use the same variable name in both cases , eg $model->links
Level 7
@Snapey Hmmm fair enough.
I named the variable data. And kept the for each second parameter as it was for clarification.
I though there would be some more magical way of doing it, I guess not :D
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