Level 1
I think this should work.
return \App\Item::where('slug', $value)->exists();
4 likes
Dec 29, 2015
4
Level 8
Best Way To Check If Record Exists
Hi there,
I have an ItemsController.php that has route model binding to the Item model:
RouteServiceProvider.php
$router->bind('items', function($value) {
return \App\Item::where('slug', $value)->firstOrFail();
});
ItemsController.php
public function show(Item $item)
{
return view('items.show', compact('item'));
}
What is the Laravel convention for checking if a record exists on this method (i.e. handling No query results for model [App\Item])? A try, catch block in the controller method?
New to Laravel. Asking about the basic standard here. Thanks in advanced!
Level 18
What you're doing is fine, would you like to display a 404 page of some sort if no model is found?
For Laravel 5.1, open up your Handler.php file in app/Exceptions and implement this into your render() method.
if ($e instanceof ModelNotFoundException) {
$e = new NotFoundHttpException($e->getMessage(), $e);
}
This now throws a NotFoundHttpException for all ModelNotFoundException's. Meaning you can simply create a 404.blade.php file in resources/views/errors and Laravel will know to use that view to display a 404 page.
But, if you're using 5.2 then you can go ahead and skip the part where you amend your Handler.php file and just create the 404.blade.php file.
Level 8
Thank you guys. This is helpful!
Actually, what I was hoping to do was to display my own custom view completely, and for this specific method. What is the Laravel standard way of catching this in a controller method?
Level 1
The answer provide dennisvdv solved my issue here.
return \App\Item::where('slug', $value)->exists();
I did; use App\Item
$answer = Item::where('slug', $value)->exists(); // this returns a true or false
Then I use if statements to handle the rest of my logic.
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