array search with array()

What have you tried? My first go would be using array_diff()

https://www.php.net/manual/en/function.array-diff.php

Hello @jeevamugunthan ,

Based on your request, I think below solution will help you. With

<?php
    $worker=array(1,2,3,4);
    $other=array(1,2,4);
    $found = [];
    $not_found = [];
    foreach($worker as $item){
        if(in_array($item, $other))
            $found[] = $item;
        else
            $not_found[] = $item;
    }
    return ['found' => $found, 'not_found' => $not_found];
?>

With using array functions

<?php
    $diff_result = array_diff($worker, $other);
    return $diff_result;
?>

In both examples, we are searching every element from $worker array in $other array.

You can visit php array_diff.

Hope this helps you.

@artcore and @abhijeet9920 thanks for your reply both are correct :)

Try this

 $worker = collect([1, 2, 3, 4]); 
 $matchingelements = $worker->concat([1, 2, 4]);


 return $matchingelements->duplicates()->count(); // this will give you count of matching elements 

//This will give you not matching values

 $worker = collect([1, 2, 3, 4]);

 $diff = $worker->diff([1, 2, 4]);


 return $diff->count();