Hello ,
this is my code :
$exceptions = [1,4,7,88,5,8]
$data = \App\User::select(['id','name','city','post_code', 'email'])->paginate(10)
->transform(function($item) use($exceptions ){
if (!in_array($item->id ,$exceptions )){
$item->email = null;
}
return $item;
});
return $data;
The problem is return $data; returns the data I need but without pagination !
Is it possible to get also the pagination ?
Thanks
Loop your pagination data and use
$data = \App\User::select(['id','name','city','post_code', 'email'])->paginate(10);
return $data;
// User.php add
public function getEmailAttribute($value)
{
return in_array($this->id, [1,4,7,88,5,8]) ? $value : null;
}
in your blade view use
$user->email
@sirik that's not possible through the model what I'm looking is to do that locally in the controller the real request is more complicated than the one I shown above .
Did my latest reply helped you out?
Maybe ->mapInto is an option for you
@godzilaravel if you use it to return json response - use resource https://laravel.com/docs/8.x/eloquent-resources#pagination
@godzilaravel , here's an example,
I pluck out the data portion of the paginate to send elsewhere
$paginate = Place::simplePaginate(20);
$this->updateMapData(collect($paginate)['data']);
return $paginate;
Not sure if this is the best practice but as @silencebringer mentioned returning the json, instead, I've also done something similar to this sample to replace the data with the transformed version.
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