uploaded multiple file function getClientOriginalName() on null

The only difference between your two code samples is that the second returns on the first iteration of your foreach loop. This suggests within the first sample that there is something within your array that is not a file object, or maybe you have a nested array.

Could you paste your form code?

The first thing I'd check is to make sure you have enctype="multipart/form-data" within your tag.

@TALINON - {!! Form::open(['method'=>'POST','action'=>'CareerController@store','files'=> true]) !!}

                                                <div >
                                                    <label id="fileT" class="choose btn  btn-default form-control {{($errors->first('filename') || $errors->first('filename.mimes') ? " error " : " ")}}" >Choose File
                                                        <input type="file"  id="f1"  name="filename[]" onchange="showname()" style="line-height: inherit;margin-top: 4%;">
                                                    </label>
                                                </div>

                                                <p id="file-name" class=" nameF" style="display:block;color: black;font-size: 14px;"></p>

                                                 <button class="btn btn-danger pull-right fa fa-trash" type="button" id="file-reset" style="margin-left: auto;border-radius: 24px;"></button>



                                                </div>

{{Form::close()}}

public function store(CareerRequest $request) { $job = Job::findOrFail($request->job_id);

    if($request->hasfile('filename'))
    {

        foreach($request->file('filename') as $file)
        {
           $name1= $file->getClientOriginalName();
            $name = time().$name1;
            $file->move('/Applications/XAMPP/xamppfiles/htdocs/careers1/storage/app/public/files', $name);
            $data[] = $name;


        }

    }
    $i=0;
    $jr=  JobReq::create([
        'job_id'=>$job->id,
        'name'=>$request->name,
        'email'=>$request->email,
        'title'=> $job->title,
        'message'=>$request->message,
        'order'=>$i,
        'rand_url' => rand(0000,9999),

    ]);

    $jr->update(['order' => 1]);

    $file = File::create([
        'filename'=>json_encode($data),
        'jobReq_id'=>$jr->id
    ]);
   
 return back();

}

it was working in laravel 5.6 but i downgrade to 5.2 then this error comes

If you want to select multiple files for upload, you need to add the multiple attribute to your input tag:

<input type="file"  id="f1"  name="filename[]" onchange="showname()" style="line-height: inherit;margin-top: 4%;" multiple>

If that doesn't solve the problem, what is the content of dd($request->file('filename')) within your controller's store method?

@TALINON - dd($request->file('filename'))

it return null

but if i did dd($request->all())

it returns the filename

What does $request->all() output?

@TALINON - array:6 [▼ "_token" => "70NoGq6zA1qKWmAlZ209I6DCoiZE9fmR6v1nkJ8p" "filename" => array:3 [▼ 0 => "IMG_2178.jpeg" 1 => "cv.pdf" 2 => "" ] ]

Try with this!

if($request->hasFile('filename')){
 dd($request->file('filename');
 }

@AMK - array:3 [▼ 0 => UploadedFile {#168 ▶} 1 => null 2 => null ]

it returns the file name but it return nothing when dd($file) outside the if conditions

pls try with only one photo not multiple! Just test it! And,how is output?

<input type="file  name="filename">

You should be getting an array of UploadedFile objects. It's not immediately clear to me why that might be. Someone else might have an idea. If something comes to mind, I'll let you know.

@AMK - yes i test it, it retrurn the right filename

I think your problem is js!

onchange="showname()"

You changed your input type 'file' to 'text' with js! Remove your js on input type file. and test with this

<input type="file  name="filename[]" multiple>

Updated!

@AMK - yes i checked, i think because of that. i will try to change it

If my answer is correct,pls can you choose best answer?

@AMK - Yes of course

glad if you sorted it.

please learn to format code properly in your questions

@SNAPEY - how to make it look good, i try but didn't find how to do it

@AMK - its actually not because of js thing. I have three input file if i upload only one or two files it give this error BUT when i upload three files it gives the right output.

format code by putting three backticks ``` on its own line before and after each block

(see the instructions at the bottom of the comment box when posting)

So,What is your problem? you should show us all code!

@AMK - its work finally. what i have done before is that i was putting foreach() for a the three file input.

 if($request->hasfile('filename'))
        {

            foreach($request->file('filename') as $file)
            {
                $name1=$file->getClientOriginalName();
                $name = time().$name1;
            }
        }

NOW , i m ding each file input alone

 if($request->hasfile('filename1')) {
            $file1 = $request->file('filename1');
            $name1 = time() . $file1->getClientOriginalName();
          
        }

 if($request->hasfile('filename2')) {
            $file2 = $request->file('filename2');
            $name2 = time() . $file2->getClientOriginalName();
        }

 if($request->hasfile('filename3')) {
            $file3 = $request->file('filename3');
            $name3 = time() . $file3->getClientOriginalName();
          
        }

I guess you'll be back the first time a user tries to upload 4 or more files.

@TALINON - I hope not. Because I specify that the user can upload one to 3 files only