Level 27
@md_imran What webcam library exactly? Have you seen https://github.com/jhuckaby/webcamjs/blob/master/DOCS.md#submitting-images-to-a-server ?
May 11, 2021
5
Level 1
How to make image file an instance of uploadFile?
Hello Artisans,
In my project, I am working with image taken by live cam. Libraray is webcam js.
like I am getting this format for image
[image] => data:image/jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAMCAgMCAgMDAwMEAwMEBQgFBQQEBQoHBwYI......
but I need this format,
[image] => Illuminate\Http\UploadedFile Object
(
[test:Symfony\Component\HttpFoundation\File\UploadedFile:private] =>
[originalName:Symfony\Component\HttpFoundation\File\UploadedFile:private] => sohid-mollah.jpeg
[mimeType:Symfony\Component\HttpFoundation\File\UploadedFile:private] => image/jpeg
[error:Symfony\Component\HttpFoundation\File\UploadedFile:private] => 0
[hashName:protected] =>
[pathName:SplFileInfo:private] => /tmp/phprzfG0R
[fileName:SplFileInfo:private] => phprzfG0R
)
can you give a concept?
Level 1
@corvs , Library is Webcam JS
here is the link- https://github.com/jhuckaby/webcamjs
Level 27
@md_imran Okay, have you checked the docs? Especially the part mentioned above.
Level 80
@md_imran You can’t, because it’s not a file; it’s Base64-encoded data. See https://developer.mozilla.org/en-US/docs/Web/HTTP/Basics_of_HTTP/Data_URIs for more details.
You can parse the URI and then store the data yourself:
[$mime, $contents] = explode(';', $request->input('image'));
// Remove "mime:" from beginning of string
$mime = str_replace('mime:', '', $mime);
// Remove "base64," from beginning of data
$contents = str_replace('base64,', '', $contents);
Storage::put('some-filename.jpg', $contents, [
'Content-Type' => $mime,
]);
Level 1
https://stackoverflow.com/questions/58509456/how-to-convert-base64-image-to-uploadedfile-laravel
I found the solution here.
Thanks All.
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