@forelse ($user->posts as $post)
<div class="col-md-6 col-lg-4">
<div class="card mb-4">
@if (!empty($post->img1))
<img src="/uploads/post_img/{{ $post->img1 }}" class="card-img-top">
@endif
<div class="card-body">
<a href="{{ route('post.show', $post->slug) }}">{{ $post->title }}</a>
</div>
</div>
</div>
@empty
<div class="card bg-secondary w-100 my-4">
<div class="card-body text-center text-light">
No posts records from {{ $user->name }}!
</div>
</div>
@endforelse
Not sure about the controller
public function show($id)
{
$user = User::find($id);
$posts = Post::paginate(6);
return view('users.show', compact('user', 'posts'))->with('i', (request()->input('page', 1) - 1) * 6);
}
In your view use as like below at the end of forelse condition,
<div>
{!! $posts->links() !!}
</div>
and in the controller use as like below,
$user = User::find($id);
$posts = Post::paginate(6);
return view('users.show', compact('user', 'posts'));
@munazzil Never use {!! !!} They can be extremely dangerous.
You just do
{{ $post->links() }}
I am using @forelse ($user->posts as $post) so do not know how to call the paginate.
Also {{$post->links()}} does not work.
My bad it should be posts not post and you put it outside your loop.
@endforelse
{{ $posts->links() }}
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