mvd

Hi @untymage

The name attribute is used to reference elements in a JavaScript, or to reference form data after a form is submitted.

https://www.w3schools.com/tags/att_form_name.asp

@adhik13th it's hard to see what is wrong without code. Can you give us the relations (code) ?

Hi @adhik13th

You pass the $practice variable/query result but in your view you use $riwayat

Hi @coachthem

Array.from not supported in IE 11 (and earlier versions), got an older IE browser?

But this will help you.

Array.from() was added to the ECMA-262 standard in the 6th edition (ES2015); as such it may not be present in other implementations of the standard. You can work around this by inserting the following code at the beginning of your scripts

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/from#Polyfill

@mstdmstd

Try this, replace

<style scoped>
    .element {
        color: $text-color;
    }

</style>

with:

@import "./resources/sass/_variables.scss"; .element { color: $text-color; }

Does this work?

Hi @mstdmstd

I think this article will help you. https://css-tricks.com/how-to-import-a-sass-file-into-every-vue-component-in-an-app/

Hi @mostafalaravel

Do you have a factory created voor the groups ?

@pol_php I don't have much server experience but maybe this article will help you ?

Enable PHP 7.2 as Default

https://tecadmin.net/switch-between-multiple-php-version-on-debian/

@lordbedwetter np, i did this steps to use Font Awesome in a project. But does it not work?

Hi @pol_php

If I check this file and line I see

 return $factory->of($arguments[0], $arguments[1])->times($arguments[2] ?? null);

The ?? is available since PHP 7.0 so I guess there is also anotherPHP version (< 7) running. Can you check which PHP version is running? You can do this in the code, file public/index.php and on top

<?php
echo phpversion();
die;

Open the app and you will see the PHP version.

Hi @lordbedwetter

You can import the scss file into your scss files (resource/sass)

@import "node_modules/font-awesome/scss/font-awesome.scss";

And run

npm run dev

@incridible thanks and i see the 'problem'. Example file with id 1 is 'Aanzi Hajar_....' but the name (user, 3) is 'Hajar' so the name is not started with 'Aanzi' = no match.

If you don't only want to match on the beginning of the name you can remove the ^ in the check. Change it to:

@if (preg_match("/" . Auth::user()->name . "/", $file->filename))

Can you also post the filenames?

@incridible now you are check if the users emailadress is literally 'filename'

I think i see what you want to check, you want to check if the beginning of the filename is the username? Better approach is to do this:

<div class="form-group">
              <form oninput="this.submit()">
                <label class="text-left">Select Student</label>
                @auth()
                    <select name="Student" id="Student" style="padding: 5px; border-radius: 3px;">
                      <option value="">Select Student</option>
                      @foreach ($files as $file)
            @if (preg_match("/^" . Auth::user()->name . "/", $file->filename))
                      <option value="{{ $file->id }}">{{ $file->filename }}</option>
            @endif
                      @endforeach
                    </select>
                @endauth
              </form>
            </div>

@incridible what you are doing is checking if the username is filename but you don't have a (user) name filename. Only (Amin, Hajar, Abdelrahman, Saeed, Zakariya)

@incridible thanks but you do a check if the name (column 'name' from table 'users') is literally filename, i think there a no user with the name 'filename'?

@joveice that could be an option, with a cron job.

who can see the energy level? I f only a user can see his/her own energy level and users are not very active you could do

• Log the timestamp when a user visit a page
• On the next page request calculate the diff in seconds from the current timestamp with the logged timestamp and update the energy level.

@incridible You do a check for username, @if (Auth::user()->name == 'filename') But i assume your uername is not really 'filename' ?

Can you give us the updated blade file?

Hi @incridible

I don't know where you get the error (in which piece of code) But this piece is not right

@if (Auth::user()->name == filename)

If think you need to use $filename or with quotes 'filename'

Hi @hunterhawley

I'm not 100% sure and not tested but hope you get an idea to get you started. You can set another relationship from a child relationship, example

->with('stats.stat_meta')

In your stats model create a relationship to stat_meta with method name stat_meta, example

function stat_meta() {
    return $this->hasMany(StatMeta::class);
}

If you want to filter on the stat_meta you could do something like

$games = App\Game::with(['stat.stat_meta' => function($q) { $q->where('stat_name', 'assist'); }]))->get();

Hi @mkumar2001

Use raw expressions, https://laravel.com/docs/5.8/queries#raw-expressions and a tutorial/article how to use this, https://fideloper.com/laravel-raw-queries

@me10071990, @snapey 's code should work. What code do you have now?

Hi @uccdev

fopen("courses.csv", "r");

You need to set the path, https://www.php.net/manual/en/function.fopen.php

fopen(public_path('courses.csv'), "r")

Hi @me10071990

Can you show us how you create the menu (blade file)?

Hi @doctolly,

I never used presenters but does this work?

$staff = $duties->staff->present(StafPresenter::class);

@me10071990 thanks

So you know the parent and you want a select input to select the childs? If this is the case.

In your controller for example (don't know if you have a model for the categories).

// Get the childs from the database
$childCategories = Categories::where('parent_id', selectedCategory)->get();

return view('another_form', compact('childCategories ');

In your form

<select name="child_category">
     @foreach($childCategories as $category)
              <option value="{{ $category->id }}">{{ $category->name}}</option>
         @endforeach
</select>

@me10071990 how do you store the categories? Does a subcategory also got a unique id for example?

@ALIYA - @aliya

dd($data['skill']); It gives result Likes :- B.edM.edNTT

This is not a array, and implode needs a array as second param.

@me10071990

Hmm do you mean you dont want the but just a one $categoryOptions based on ````$selectedCategory`````

You can this by

$selectedSubCategory = $categoryOptions [$selectedCategory ];

But you see there are more indexes with the same id (7 x 0, 3 x 4 and 3 x 6) so make your index for the $categoryOptions unique.

@ALIYA - Can you give us the whole file code where you set this implode. And give us the output of $data['skill']

dd($data['skill'])

Hi @aliya

And how can we help you without knowing your code?

@me10071990 hmmm no not really because you can't have children in a select. You can do a sort of workaround with a '-' before a child. Parent 1 Parent 2

• child 1 for parent 2
• child 2 for parent 2 Paren 3
• child 1 for parent 3

But a pretty solution is to create a select with just the parants and if you pick one, show another select with the children from the selected parent.

Example, https://jsfiddle.net/hibbard_eu/yb0koLdc/

and when trying with and showing also "compact(): Undefined variable: selectedCategory " I think you don't you have a $selectedCategory in your controller ?

Hi @me10071990

Something like this?

In your controller to call 'another form'

$selectedCategory = 5;
        $categoryOptions = array(
            1 => 'home',
            2 => 'contact',
            3 => 'about',
            4 => 'youth',
            5 => 'people',
            6 => 'peace',                
        );
return view('another_form', compact('selectedCategory ', 'categoryOptions'));

I asome the categories is a select

  <select name="category">
     @foreach($categoryOptions as $index => $option)
              <option value="{{ $index }}" @if($index == $selectedCategory) selected @endif>{{ $option }}</option>
         @endforeach
</select>

Hi @phphupptechnologies

In file app\Http\Controllers\Auth\RegisterController.php method validator

The validator for the password, only for the repeating chars (don't know it for the following)

 'password' => ['required', 'string', 'min:8', 'confirmed', 'regex:/^(?!.*(\w){1,}).+$/'],

@deekshith

There are some api to do that (but my solutions are not really good/user friendly) https://github.com/vimeo/vimeo.php#uploading-videos and a Laraval package https://github.com/vimeo/laravel

Hi @deekshith,

Your solutions will unfortunately not work because the only real protection is the domain validation. If someone know the source, he/she can always access the video.

You could set a password protection on the video's with the api every x time and notify a user when he/she logs in for the new password....but that is not very user friendly ;) Or delete and insert the video's every x time with the api and update the url in your db...also not a good approach.

@harshitbatra

Whats is the user name where you get a 'not found page' ? And can you give us the user factory code?

@raj123,

Check this package, https://github.com/LifeOnScreen/laravel-quickbooks

Hi @gaan10

hospital_incharge_referred is your model?

Try

for($count = 0; $count < count($Patient_Name); $count++)
      {
       $data = array(
          'Patient_Name' => $Patient_Name[$count],
          'Mobile'  => $Mobile[$count],
          'Surgeon' => $Surgeon[$count],
          'Amount'  => $Amount[$count]
          );

          hospital_incharge_referred::insert($data);
      }

@irankhosravi

You are not closing {{ route('sendAgainCode')}}, closing " is missing.

And you set a get request (link to a page = get request) and in your router file you defined a post

Change the router request to

Route::get('/send-again-code', '[email protected]')->name('sendAgainCode');

@irankhosravi a clear, can you give is the blade/source template where you set 'Send code again' link/button?

@harshitbatra what you can do is change the factory to create a dummy user to avoid the dots.

In file database/factories/modelfactories.php (or in newer versions, UserFactory.php), change

$factory->define(User::class, function (Faker $faker) {
    return [
        'name' => $faker->name,
    ....

to

$factory->define(User::class, function (Faker $faker) {
    return [
        'name' => $faker->firstName . ' ' . $faker->lastName,
    ....

@harshitbatra

I think because the dot (special char) in the name, can you check if this is the case?

@irankhosravi and if you change

<form action="{{ route('send') }}" method="post">

to

<form action="{{ route('sendAgainCode') }}" method="post">

?

@irankhosravi because we don't know what the form action is.

Can you give us the template source/blade code for this form?

Hi @kakallatt

Set a maximal crawl count?

By default, the crawler continues until it has crawled every page of the supplied URL. If you want to limit the amount of urls the crawler should crawl you can use the setMaximumCrawlCount method.

// stop crawling after 5 urls

Crawler::create()
    ->setMaximumCrawlCount(5)

https://github.com/spatie/crawler

@phoenix5 you need to post the value with ajax (or add the value in a hidden value and post a form).

Something like (not tested)

$('.dropdown-menu- li a').on('click', function() {

    var selectedValue = $(this).text();
    var id = 1; //1 is just for testing,  you need to get the id somewhere with ajax.
        $.ajax({

           type:'POST',

           url:'/ajaxRequest',

           data:{produit:id, modele:selectedValue },

           success:function(data){

              alert(data.success);

           }

        });
});

Route

Route::post('ajaxRequest', '[email protected]');

In your controller

    public function ajaxPost(Request $request)

    {
$data = Input::all();

        $pr = new Produit([
                    'produit'              => $data['produit'],
                    'modele'               =>  $data['modele'],
                    ...
                ]);
 $pr->save();

    }

@van1310, ofcourse $interviewschedule is a collection, try this

@if(empty($interviewschedule)) 
    Data empty
@elseif($interviewschedule->first() == "basic")
        Has Basic Data
@else
        False
@endif

Hi @van1310

I think interviewschedule is already your round_type variabele And your ifelse check does not work, i changed this for tou.

Can you check if this work?

@if(empty($interviewschedule)) 
    Data empty
@elseif($interviewschedule == "basic")
    Has Basic Data
@else
    False
@endif