david19

Hello Team. I would like add a button with my composer package, in the view. (View of App).... I can make new views, but not elements :( There are a little trick?

Because here in germany, the courses are really bad. I watch only courses in english on laracasts, youtube or udemy. I love this method for learning, and i get better and better with laravel. I posted over 30 questions in this forum, and i get allways nice answers, which put me to the right way :)

You need a basic knowhow on vuex and websockets. After that, you can choose your next step.

I saw many courses with laravel websockets or vuex. You can create realtime apps with this.

You can create a realtime chat with a websocket or with Vuex. Vuex storeing the data in a container.

What is the better approach? I dont know this, because i am new in Vuex, and i am new for websockets :)

Hello Team, simple Question:

1. I will buy a extra server on digital ocean via forge. On this server i will install only the laravel websocket (beyondco).

2. I will buy a second server for my projects. Can i use this websocket for all projects which stands on other server?

If yes, how difficult is that? Because then, i will use only pusher.com. Its not free, but very easy. And i can use for all projects.

Example: Maby we are a Developer. We create a Laravel Backend API with Passport.

It would be nice, only 1 Laravel Backend for all clients. The Problem is the databases. Every Client need a extra database. All clients use the api, but a extra database. For the developer its great, because he create only 1 Laravel Backend API.

There are a easy simple way for that? Many thanks :)

Its not easy, find good informations. Maby some members here find a answere.

1. Standart: Laravel + Blade + Cache + CDN  Backend: "Laravel" Frontend: "Laravel" little vue or react or angular

2.  Laravel + Vue + Vuex + Vrouter + Cache + CDN  Backend: "Laravel" Frontend: "Vue,Vuex,Vrouter"

3. Laravel + Nuxt.js + CDN Backend: "Laravel Api with Passport or JWT" Frontend: "Nuxt only"

What is the fastest technique for Loadspeed and User smoothness? I know, this question is not easy, but we can all put our experience here.

Many thanks for answers :) Okay i understand now.

Hello Team,

On Youtube and Udemy i watch many videos with Laravel backend + Vue Frontend. It is becoming popular. The Vue Frontend use the backend laravel Api for show posts or something.

My question is, why this combination is popular? Why not use Laravel for frontend,too.? Or Laravel with a little bit vue as combination.

In the videos i saw "routes" with the VUE Routing. Thats nice but why? And can google all read the js.code? (googlebot). Thanks for answers :)

Thanks for your answere. I try a little trick now, but it doesnt work :(

I created a package with only controllers. Example: mypackage/src/Http/Controllers/LoginController

This Controller should extend the Login Controller from the Auth Package and add this function:

<?php


namespace Extrem16\Auth\Http\Controllers;


use App\Http\Controllers\Auth\LoginController;



class AuthExtrem16Controller extends LoginController

{
  public function showLoginForm()
  {

      return 'my package work';

  }
}

Hello team,

i will create packages. I can make views, controllers,models,routes. This works. But how i can add functions in views, which are default?

Example Package: Add this function in /app/Http/Controllers/Auth/LoginController

public function showLoginForm()
    {

        return view('vendor.mytheme.auth.login');
        
    }

For this function i can not create a extra controller, because its the default laravel auth package.

Yes!! Many thanks Sinnbeck :D

Sorry its not work :( Yes i can access the url manually.

<?php
$file = 'my-dev.zip';
$path = pathinfo(realpath($file), PATHINFO_DIRNAME);
$zip = new ZipArchive;
$res = $zip->open($file);
if ($res === TRUE) {
  $zip->extractTo($path);
  $zip->close();
  
header("Location: http://localhost/install.php");

} else {
  echo "Die Datei $file konnte nicht gefunden/ge&ouml;ffnet werden.";
}
exit;
?>

I dont understand :(

Its not work :( After unzip all files, stands on the current site :( Maby its the .htaccess?

RewriteEngine on
RewriteCond %{REQUEST_URI} !^public
RewriteRule ^(.*)$ public/ [L]

Hello Team. With this php, i will unzip my laravel folders. But after this, i will redirect to a other php file. The redirect doesnt work :(

<?php



$file = 'my-dev.zip'; //Dateiname entsprechend �ndern

$path = pathinfo(realpath($file), PATHINFO_DIRNAME);

$zip = new ZipArchive;
$res = $zip->open($file);
if ($res === TRUE) {
  $zip->extractTo($path);
  $zip->close();
  
header('/install.php');

} else {
  echo "Die Datei $file konnte nicht gefunden/ge&ouml;ffnet werden.";
}

exit;
?>

Solved: I found gitbash :D

Hello Team. I am a littlebit i'm confused :(

I will test laravel forge. All its fine. Setup the server and all works nice :) I made a fresh laravel app via composer on my windows10. Now i will put this new laravel app, to my git repository. If i type the first command:

git init

or

git status

My cmd on win10 doesnt found the commands. All tutorials which i see, its on mac or linux. My new Server on Forge works, but i can not push my laravel app to github :P

Hello Team. I love the chunk method, for build a collection in the views. But now i have a @include, and i get error. I try use chunk in a card-deck.

<div class="card-deck">
@foreach ($product_categories as $product_category)
          <li>{{ $product_category->name }}</li>
          <ul>
          @foreach ($product_category->childrenCategories as $childCategory)
          @include('admin.shop.category.child_category', ['child_category' => $childCategory])
          @endforeach
          </ul>
          @endforeach
</div>

The problem is this @include file:

{{ $child_category->name }}
@if ($child_category->product_categories)
    <ul>
      @foreach ($child_category->product_categories as $childCategory)
          @include('admin.shop.category.child_category', ['child_category' => $childCategory])
      @endforeach
    </ul>
@endif
</div>

@foreach($product_categories->chunk(3) as $chunk)

@foreach ($chunk as $product_category)

Maby its not possible use chunk with @include :(

@tisuchi Holy Shit, This works!!!!!!!!!!!!!!!!!!!!!

public function sub_categories($category_slug)
    {
$categories = Category::where('category_slug',$category_slug)->with('childrenCategories')->get();
return $categories;

    }

    
0   
id  20
created_at  "2019-11-28 05:32:53"
updated_at  "2019-11-28 05:32:53"
name    "Men"
parent_id   null
category_slug   "men"
description null
image   null
title   "Men"
alt_img null
canonical_org   null
canonical_new   null
robots  1
meta_description    null
children_categories 
0   
id  22
created_at  "2019-11-28 05:34:25"
updated_at  "2019-11-28 05:34:25"
name    "Jeans"
parent_id   20
category_slug   "jeans"
description null
image   null
title   "Jeans"
alt_img null
canonical_org   null
canonical_new   null
robots  1
meta_description    null
product_categories  
0   
id  24
created_at  "2019-11-28 05:37:31"
updated_at  "2019-11-28 05:37:31"
name    "Blue Jeans"
parent_id   22
category_slug   "blue-jeans"
description null
image   null
title   "Blue Jeans"
alt_img null
canonical_org   null
canonical_new   null
robots  1
meta_description    null

Soo many thanks :D

I follow exact this tutorial here: https://laraveldaily.com/eloquent-recursive-hasmany-relationship-with-unlimited-subcategories/

Hello Team, sorry i need help again.

I have a categories table with unlimited subcategories.

ID##Name                ##Parent_ID          ##Category_slug
20##Men                 ##Null                     ##men
21##Women           ##Null                     ##women
22##Jeans               ##20                        ##jeans
23##Leggings        ##21                        ##jeans
24##Blue Jeans          ##22                        ##jeans
25##Red Leggings     ##23                        ##jeans

I made a route for the Shop View, which works fine :)

Route::get('/shop', 'Shop\Category\[email protected]_categories')

public function all_categories()
    {
      $categories = Category::whereNull('parent_id')->get();

      return $categories;
    }

0   
id  20
created_at  "2019-11-28 05:32:53"
updated_at  "2019-11-28 05:32:53"
name    "Men"
parent_id   null
category_slug   "men"
description null
image   null
title   "Men"
alt_img null
canonical_org   null
canonical_new   null
robots  1
meta_description    null
1   
id  21
created_at  "2019-11-28 05:33:03"
updated_at  "2019-11-28 05:33:03"
name    "Women"
parent_id   null
category_slug   "women"
description null
image   null
title   "Women"
alt_img null
canonical_org   null
canonical_new   null
robots  1
meta_description    null

Now i will try get only the subcategories.

Route::get('/shop/{category_slug}', 'Shop\Category\[email protected]_categories')

public function sub_categories(Category $category_slug)
    {

      $categories = Category::whereNotNull('parent_id')->get();

      return $categories;

    }

I visit localhost/shop/men (or women)

But i get all subcategories :(

0   
id  22
created_at  "2019-11-28 05:34:25"
updated_at  "2019-11-28 05:34:25"
name    "Jeans"
parent_id   20
category_slug   "jeans"
description null
image   null
title   "Jeans"
alt_img null
canonical_org   null
canonical_new   null
robots  1
meta_description    null
1   
id  23
created_at  "2019-11-28 05:34:54"
updated_at  "2019-11-28 05:34:54"
name    "Leggings"
parent_id   21
category_slug   "leggings"
description null
image   null
title   "Leggings"
alt_img null
canonical_org   null
canonical_new   null
robots  1
meta_description    null
2   
id  24
created_at  "2019-11-28 05:37:31"
updated_at  "2019-11-28 05:37:31"
name    "Blue Jeans"
parent_id   22
category_slug   "blue-jeans"
description null
image   null
title   "Blue Jeans"
alt_img null
canonical_org   null
canonical_new   null
robots  1
meta_description    null
3   
id  25
created_at  "2019-11-28 05:37:45"
updated_at  "2019-11-28 05:37:45"
name    "Red Leggings"
parent_id   23
category_slug   "red-leggings"
description null
image   null
title   "Red Leggings"
alt_img null
canonical_org   null
canonical_new   null
robots  1
meta_description    null

The View if "men" should only show "Jeans". Sorry for the long text :(

Hello Team. I dont understand why PHP do that. Because i am a beginner. I have a Edit View with 2 Formgroups:

<div class="form-group">
          <div class="card bg-darkblue text-white border border-white">
          <div class="card-header bg-darkblue text-white">
          CHANGE PARENTCATEGORY?
          </div>
          <div class="card-body bg-darkblue text-white">
          <label for="exampleFormControlSelect1"></label>
          <select  name="parent_id" class="form-control bg-darkblue text-white" id="exampleFormControlSelect1">
          <option value="0">No</option>
          @foreach($product_categories as $product_category)
          <option value="{{$product_category->id}}">{{$product_category->name}}</option>

          @endforeach
          </select>
          </div>
          <div class="card-footer bg-darkblue text-white">
          </div>
          </div>
          </div>

<div class="form-group">
          <div class="card bg-darkblue text-white border border-white mt-5">
          <div class="card-header bg-darkblue text-white">
          CATEGORY DESCRIPTION
          </div>
          <div class="card-body bg-darkblue text-white">
          <textarea class="form-control" id="summernote" rows="3" name="description" value="{{$product_category->description}}">{{$product_category->description}}</textarea>
          <script>
          $('#summernote').summernote({
          placeholder: '',
          tabsize: 2,
          height: 100
          });
          </script>
          </div>
          <div class="card-footer bg-darkblue text-white">
          </div>
          </div>
          </div>

Why this foreach loop override my Textvalue in the Textarea? I closed the loop before, i dont understand. If i change the loop name:

@foreach($product_categories as $product_cat)
          <option value="{{$product_category->id}}">{{$product_cat->name}}</option>

          @endforeach

it will works, but then it will not save the parent category.

@tisuchi Many thanks :D

Hello Team.

I have a categorie Table with unlimted Subcategories

Id### Name###Parentid
1 ### Car ### Null
2 ###Bmw### 1
3 ###Ford###  1

When i go to my "EDIT" Page, i can choose my parent category. But the problem is, when i go to the "Ford" Edit Page, i can set "Ford" as Parent. But this is not correct. Ford can not a parent of Ford. Now i try to fix this, but i can not fix this. I need all categories which as not the "ID", which i edit. This is what i try now:

$category = category::find($id);
$categories = category::doesntHave('????')->get();

Hello Team, I have a question.

For compile styles i need npm. Example: I will add a bootstrap Root:Class Color. After that i compile this with NPM. All its good.

Now i will put my laravel on the live server. Should i unistall all NPM Files via composer? Or its that not necessary?

Hello Team,

How much reduce includes the performance in blade files? I like this example here, because its much more readable and very clean. I mean put all cards via includes :)

@extends('layouts.app')
@section('inline-css')
<style></style>
@endsection
@section('main-css')
<link href="{{ asset('assets/css/bootstrap.min.css') }}" rel="stylesheet">
@endsection
@section('content')
<div class="container bg-light rounded text-white">
<div class="row">
@include('admin.layouts.sidebar')
<div class="col-xs-12 col-sm-12 col-md-10 col-lg-10 col-xl-10">
@include('card.1')
@include('card.2')
@include('card.3')
@include('card.4')
@include('card.5')
@include('card.6')
@include('card.7')
</div>
</div>
</div>
@endsection
@section('scripts')
<script src="{{ asset('assets/js/jquery-3.4.1.min.js') }}"></script>
<script src="{{ asset('assets/js/bootstrap.min.js') }}"></script>
@endsection

@tray2 Yes, the checkbox are better, but checkbox allows multiple selects. Can you show me a example with <18 or >18 please?

I found a very go way for me. I think its the best. Put this over the @foreach in the radio form:

<input type="radio" class="radio" name="parent_id" value="0" checked> No Parent Category

In the controller:

if($request->parent_id == 0)
      {
        $category->parent_id = NULL;
      }

Thats it! :D

Hello Team, I use Laravel 6 with Bootstrap: I saw a new problem. I have Categories with Parent Categories. If i check a radio button, then i can not uncheck in my form.

Yes, i can make a standart category_base, and make a if statement and set parent_id to "NULL". But the problem is, in the future i loaded allways this category_base in my "foreach" blade files. I think that is not the best solution.

How you deal with this? Do you make this with javascript, all what is the best way? Many thanks.

There are any tutorial for create a installer for a laravel application? You know the installers of wordpress or october cms. Maby laracasts?? But i dont find a tutorial. There are a package on github, but this is only for the migrations.

I think this works:

 $categories = category::where('category_slug',$category_slug)->with('categories')->get();

Thanks Nakov, i know. But now i get only "cars" without Subcategories.

localhost/shop/cars

0   
id  1
name    "Cars"
parent_id   null
category_slug   "cars"
created_at  "2019-11-21 00:00:00"
updated_at  "2019-11-21 00:00:00"

But i need all subcategories in cars.

0   
id  2
name    "BMW"
parent_id   1
category_slug   "bmw"
created_at  "2019-11-21 00:00:00"
updated_at  "2019-11-21 00:00:00"
1   
id  3
name    "Ford"
parent_id   1
category_slug   "ford"
created_at  "2019-11-21 00:00:00"
updated_at  "2019-11-21 00:00:00"

That is the problem if i use RouteKeyName :(

Hello Team, sorry for the question again, but i tryed many hours before :)

ID 1: Cars = parent_id = NULL
ID 2: BMW = parent_id = 1
ID 3: Ford = parent_id =  1
ID 4: Bikes = parent_id = NULL
ID 5: Cross-Bike = parent_id = 4

With this Line i get all subcategories with the id.

public function subcategories($id)
    {
      $categories = category::where('parent_id',$id)->get();
      return $categories;

    }

localhost/shop/1

0   
id  2
name    "BMW"
parent_id   1
category_slug   "bmw"
created_at  "2019-11-21 00:00:00"
updated_at  "2019-11-21 00:00:00"
1   
id  3
name    "Ford"
parent_id   1
category_slug   "ford"
created_at  "2019-11-21 00:00:00"
updated_at  "2019-11-21 00:00:00"

Instead of ID, i like the category_slug "cars".

localhost/shop/cars

Route::get('/shop/{category_slug}', 'Shop\Product\[email protected]')

public function subcategories($category_slug)
    {
      $categories = category::where('parent_id',$category_slug)->get();
      return $categories;

    }

I get nothing :(

Yes that works. Many thanks! But when i go to localhost/shop/bikes, i get BMW and Ford, because i use parent_id = 1. I use RouteKeyName

Yes, i can make a new line for the Bikes, but it is possible in automatic? I can not make a new line for all Subviews :)

Hello Team,

ID 1: Cars = parent_id = NULL
ID 2: BMW = parent_id = 1
ID 3: Ford = parent_id =  1
ID 4: Bikes = parent_id = NULL
ID 5: Cross-Bike = parent_id = 4

I would like a view with only BMW and Ford. But i get allways with the Cross Bike :( Relationship Category Model

return $this->hasMany('App\Category', 'parent_id');

public function subcategories()
    {
      $categories = Category::where('parent_id')->???->get();
    }

Ohh sorry Sinnbeck. Now it works!! I tryed before this:

Public function product( Category $category, Product $product, $id )

But the ID must stay on first place.

public function product($id, Category $category, Product $product)

Sinnbeck you are my men! Many thanks :D

Yes, exactly! If i use this, i get the url witout view, because i need a Eloquent.

Hello Team, My url for the single view works fine with RouteKey. This works for me:

Route::get('/shop/{category}/{product}', 'Shop\Product\[email protected]')->name('guest.shop.product.product');

public function product(Category $category, Product $product)
{

    return view('guest.shop.product.product',compact('product','category'));

}

I can see my view here: This works! http://localhost/shop/water/smoke-intro

But now i will put my id before. This:

Route::get('/shop/{id}/{category}/{product}

How i can use Eloquent with my setup? I tryed many thinks, but it doesnt work. Many thanks for help.

This found my mistake. Many thanks Nakov. I made a mistake in my table column. It wars "Category_id" and not "category_id".

My forms works great. But for my edit view, the checked mark doesnt work.

I have a relationship Product with Categories.

If the Category_id ( Table:Products) , same as ID (Table:Categories), it should be checked! This not work..

@foreach ($categories as $category)
<label>
<input type="radio" name="category_id" id="optionsRadios1" value="{{$category->id}}" @if ($product->category_id == $category->id) checked @endif>
</label>
{{ $category->name }}
<br>
@endforeach

Ahh Okay many thanks.

The problem is, the user must upload all the files and migrate his database. Sure, you can use a laravel installer, for easy steps. But he can not update the core, if i make changes. I think the simple way is, same wordpress. You get a message, "Update now". And the application update your core.

I mean only the public folder. But i dont know. I think the PHP Code,too. Because the application can create posts etc....

Hello Team, i have a question again.

Example: I upload my laravel App to my ftp server.

Its possible upload the public files on my friend ftp and connect to my laravel core files?

Laravel Core Files stands on my IP adress, and the Public Files stands on different IP.

If the answere "Yes", how reduce the performance?

Many thanks guys! Change the format works! Many thanks!

public function categories()
    {
        return $this->hasMany('App\Category', 'parent_id');
    }

    public function childrenCategories()
{
    return $this->hasMany('App\Category','parent_id')->with('categories');
}

The Traceback show me this:

C:\xampp\htdocs\developer\extrem16-base-1.0\vendor\laravel\framework\src\Illuminate\Database\Connection.php:665

     * @throws \Illuminate\Database\QueryException

     */

    protected function runQueryCallback($query, $bindings, Closure $callback)

    {

        // To execute the statement, we'll simply call the callback, which will actually

        // run the SQL against the PDO connection. Then we can calculate the time it

        // took to execute and log the query SQL, bindings and time in our memory.

        try {

            $result = $callback($query, $bindings);

        }

 

        // If an exception occurs when attempting to run a query, we'll format the error

        // message to include the bindings with SQL, which will make this exception a

        // lot more helpful to the developer instead of just the database's errors.

        catch (Exception $e) {

            throw new QueryException(

                $query, $this->prepareBindings($bindings), $e

            );

        }

 

        return $result;

    }

 

    /**

     * Log a query in the connection's query log.

     *

     * @param  string  $query

     * @param  array   $bindings

     * @param  float|null  $time

     * @return void

     */

Hello Team. I have a relation table "categories" with a column ForeignKey"category_id". It works all fine. But now i will change the name. "category_id" --> "parent_id". I deleted the table, and i made a new migration. Now the database is correct and shows "parent_id". I changed all my files and replace "category_id" with "parent_id". All is clean now. But laravel give me a error.

SQLSTATE[42S22]: Column not found: 1054 Unknown column 'categories.category_id' in 'where clause' (SQL: select * from `categories` where `categories`.`category_id` in (1)) 

Laravel search for the category_id column, but i changed all files to parent_id. How i can fix this? Should i delete the model, and remake them??

OHHHH, now it works!!!!!!! Thank you soo much sir :)

This wars the edit view, for my categories. I build a category tree. This foreach come from the controller:

public function edit($id)
    {
        $category = Category::find($id);
        $categories = Category::paginate(5);
        return view('admin.shop.category.edit',compact('category','categories'));
    }

The foreach loop is closed, but dont know where is the mistake. Should i move the Delete form in a other view?

@extends('layouts.app')
@section('inline-css')
<style></style>
@endsection
@section('main-css')
<link href="{{ asset('assets/css/bootstrap.min.css') }}" rel="stylesheet">
@endsection
@section('content')
<!--container   -->
<div class="container">
<!--main row   -->
<div class="row">
<!--main col-12 -->
<div class="col-xs-12 col-sm-12 col-md-12 col-lg-12 col-xl-12">
<div class="card">
<div class="card-header bg-dark text-white">
<h2>Create a Category</h2>
</div>
<div class="card-body text-center">
<!--1. row -->
<div class="row">
<!--1. col-12 -->
<div class="col-xs-12 col-sm-12 col-md-12 col-lg-12 col-xl-12">
<div class="card">
<div class="card-header bg-dark text-white">
Create a Category
</div>
<div class="card-body">

  <form method="POST" action="{{route('admin.shop.category.update',$category->id)}}">
  @method('PUT')
  @csrf

  <div class="form-group">
    <label for="name">Name</label>
  <input type="text" class="form-control" placeholder="" name="name" value="{{$category->name}}">
  </div>

  <div class="form-group">
    <div class="radio">
  @foreach ($categories as $category)
  <label>
  <input type="radio" name="category_id" id="optionsRadios1" value="{{$category->id}}">
  <div class="card">
  {{$category->name}}
  </label>
  </div>
  <br>
  @endforeach
  </div>
  </div>
{{ $categories->links() }}
</div>
<div class="card-footer">
  <input type="submit" class="btn btn-primary" value="Submit">
</form>

<form method="POST" action="{{ route('admin.shop.category.destroy',$category->id )}}">
  @method('DELETE')
  @csrf
<input type="submit" class="btn btn-danger float-right" value="Delete">
</form>


</div>
</div>
<!--end 1. col-6 -->
</div>

<!--end 1. row -->
</div>
</div>
</div>
<div class="card-footer bg-dark text-white">
<a class="btn btn-warning" href="{{route('admin.shop.category.index')}}" role="button">Back</a>
</div>


<!--end main col-12 -->
</div>
<!--end main row   -->
</div>
<!--end container   -->
</div>
@endsection
@section('scripts')
<script src="{{ asset('assets/js/jquery-3.4.1.min.js') }}"></script>
<script src="{{ asset('assets/js/bootstrap.min.js') }}"></script>
@endsection

Yes here is the mistake. I get allways the last input, when i click delete. The correct ID is "88" not "110".

array:5 [▼
  "id" => 110
  "created_at" => "2019-11-17 05:35:32"
  "updated_at" => "2019-11-17 05:35:32"
  "name" => "Kleidung"
  "category_id" => null
]

Its the same result. I dont know, what is this :D Maby its a loop problem?