tisuchi

@rhugvedadesai98

I have the same issue before.

Check these steps. I figure it out this way

http://laravel-school.com/snippet/how-to-add-bootstrap-in-vuejs-43

@rhugvedadesai98

I have the same issue before.

Check these steps. I figure it out this way

http://laravel-school.com/snippet/how-to-add-bootstrap-in-vuejs-43

@van-india

It's because bed is the property of your $list object.

If you want to use count(), then you need to use it on the $list object.

For example-

{{ $list->count() }}

@ahmed_bondok2006

It's because you haven't passed two parameters in AllProductController constructor. You have to pass two parameters there since you defined two arguments in the constructor of your controller.

@van-india

It's because bed is the property of your $list object.

If you want to use count(), then you need to use it on the $list object.

For example-

{{ $list->count() }}

@hsntngr

For your case, if it is only for a long time waiting issue, then check this discussion. I believe you will find the right solution there-

https://stackoverflow.com/questions/31449434/handling-expired-token-in-laravel

@hsntngr

In that case, you have to make sure that in your post submission, you have set csrf token properly

For example-

<form action="/some/action" method="POST">
    @csrf

    ...
    

Check more: https://laravel.com/docs/6.x/csrf

@neeraj1005

Actually @tray2 suggested the link to make your life easier. The intervention is a well-known image manipulation package in PHP.

Of course, there are other way around where you need to do a lot. You can check it in the php documentation.

This is a sample function. There are more functions you can search for based on your requirements. https://www.php.net/manual/en/function.getimagesize.php

@hsntngr

It seems it's the CSRF issue.

Have you set up the CSRF properly?

BTW, are you using ajax for the post request or Laravel form directly?

@brltdxd

There are many ways to figure it out. You can go with @tray2 solution.

Or you can simply try this-

...

'product_id' => $product = factory(Product::class),
'original_price' => $product->product_id,
...

Or you can call it on top of your return.

$factory->define(OrderProduct::class, function (Faker $faker) {
    $product = factory(Product::class);
    
    return [
        'order_id' => factory(Order::class),
        'product_id' => $product,
        'original_price' => $product->product_id, /* Must use the price generated from 'product_id' */
        'quantity' => $faker->randomDigitNotNull,
    ];
});

And of course, you may find some other way around, if you search more.

@hnkorap88

No, Dockerfiles are single containers (services) by design as I know so far. Laradock provides a docker-compose file that references multiple dockerfiles. However, you could create a smaller docker-compose file that only starts the containers you need (let's say a webserver with php, a database server and redis).

Laradock ships with a way to many containers in docker-compose, that is why the tutorial tells you to specify which containers you want to run.

Check more: https://laradock.io/getting-started/

docker-compose up -d nginx mysql

But if you specify a minimal docker-compose.yml, you just can type

docker-compose up -d

without any additional arguments

@snapkwi

The parameters sent with the redirect function are added to the query string of the generated url. So if you want to access them in the other controller's function, you have to get the value from the request object.

For example-

class ControllerTwo extends Controller
{
    public function index()
    {
        $SetNumber = request()->get('SetNumber');

        return view('pages.spotifyApi')->with('SetNumber', $SetNumber);
    }
}

@snapkwi

The parameters sent with the redirect function are added to the query string of the generated url. So if you want to access them in the other controller's function, you have to get the value from the request object.

For example-

class ControllerTwo extends Controller
{
    public function index()
    {
        $SetNumber = request()->get('SetNumber');

        return view('pages.spotifyApi')->with('SetNumber', $SetNumber);
    }
}

@timmypro

Can you show your CountryController?

@brad_fresh99

I think your relations goes like this:

Stores -> (n*n)StoreProducts -> Products -> (n*1)Brands

which StoreProducts is a joining table between Stores and Products. With this assumption, I would use something like this:

In the Store model,

public function products(){
    return $this->belongsToMany(\App\Product::class, "store_products"); 
}

In the Products model,

public function stores(){
    return $this->belongsToMany(\App\Store::class, "store_products");
}

In the StoreProducts model,

public function store(){
    return $this->belongsTo(\App\Store::class);
}

public function product(){
    return $this->belongsTo(\App\Product::class);
}

This way the relationship is created. Then you can use something like this:

$stores = \App\Store::whereHas("products", function($q) use ($brandId){
    return $q->where("brand_id", $brandId);
});

This will give you the stores in which the brand exists.

@hnkorap88

No, Dockerfiles are single containers (services) by design as I know so far. Laradock provides a docker-compose file that references multiple dockerfiles. However, you could create a smaller docker-compose file that only starts the containers you need (let's say a webserver with php, a database server and redis).

Laradock ships with a way to many containers in docker-compose, that is why the tutorial tells you to specify which containers you want to run.

Check more: https://laradock.io/getting-started/

docker-compose up -d nginx mysql

But if you specify a minimal docker-compose.yml, you just can type

docker-compose up -d

without any additional arguments

@brad_fresh99

I think your relations goes like this:

Stores -> (n*n)StoreProducts -> Products -> (n*1)Brands

which StoreProducts is a joining table between Stores and Products. With this assumption, I would use something like this:

In the Store model,

public function products(){
    return $this->belongsToMany(\App\Product::class, "store_products"); 
}

In the Products model,

public function stores(){
    return $this->belongsToMany(\App\Store::class, "store_products");
}

In the StoreProducts model,

public function store(){
    return $this->belongsTo(\App\Store::class);
}

public function product(){
    return $this->belongsTo(\App\Product::class);
}

This way the relationship is created. Then you can use something like this:

$stores = \App\Store::whereHas("products", function($q) use ($brandId){
    return $q->where("brand_id", $brandId);
});

This will give you the stores in which the brand exists.

@chris1981

Again it depends on what kinds of api you want to build and which part exactly you want to protect via token.

If I get you correctly, just imagine that you want to create an API for a blog.

// Public routes
GET     /articles           
GET     /article/slug       

// Protected routes
GET     /article/create     - middleware: auth:api
POST    /article/store      - middleware: auth:api
GET     /article/update     - middleware: auth:api
PUT     /article/put        - middleware: auth:api
...
...

Here, for accessing the public routes, your clients doesn't need to have the access token.

Correct me if I am wrong.

@alexgodbehere79

Have you renamed all the id columns to include the resource name, eg professions_id. I think it is required. Although make sure that you have changed that as described in the documentation.

It turns out that changing the column name is unnecessary, and actually creates this error. So leave them as id. Note that you can actually change column names, it's just that in this case (with Nova) it resulted in an error.

@brltdxd

You should have another factory for product, then you can easily do this way-

'original_price' => factory(Product::class)->create()->product_id

The full code will be like this-

$factory->define(OrderProduct::class, function (Faker $faker) {
    return [
        'order_id' => factory(Order::class),
        'product_id' => factory(Product::class),
        'original_price' => factory(Product::class)->create()->product_id, /* Must use the price generated from 'product_id' */
        'quantity' => $faker->randomDigitNotNull,
    ];
});

@alexgodbehere79

Have you renamed all the id columns to include the resource name, eg professions_id. I think it is required. Although make sure that you have changed that as described in the documentation.

It turns out that changing the column name is unnecessary, and actually creates this error. So leave them as id. Note that you can actually change column names, it's just that in this case (with Nova) it resulted in an error.

@alexgodbehere79

Do the laravel logs contain any errors?

@brad_fresh99

Do you want the stores which contain a brand?

@brad_fresh99

Try this:

{!! Form::model($post, ['action' => ['[email protected]', $post->id], 'method' => 'PUT']) !!}

If your route is a resource:

Route resource

Route::resource('post','PostController');

Form update

{!! Form::model($post, ['route' => ['post.update', $post->id], 'method' => 'PUT']) !!}

@beracah.kings

You better show your code here. SQL Injection always depends on the way you write your code.

@chris1981

Since API is stateless, so you have validated updates or creates data. In that case, I cannot think anything else except tokenization.

Now the question is do you want to generate your own token system or use the passport. Of course, I will prefer to use laravel passport in this scenario because it will reduce your workload and will give you an updated and competible code with the different versions of laravel all the time.

@a4family

What if you try this?

$milestones = str_replace(array('[', ']', '"'),'',$milestones);

Since you try to remove square brackets and double-quotes.

@myszon

Could you try adding in your config/filesystems.php file a user_images key:

'user_images' => [
    'driver' => 'local',
    'root'   => public_path() . '/storage/',
],

After that, try in your code to access via useR_images by doing below:

Storage::allFiles('user_images');

Check more: https://laravel.com/docs/5.0/filesystem#basic-usage

@girliosalama95

Anyways, you can reset the $limit property:

$query = TestModel::where('a', 'b')->limit(100);
$query->limit = null;
$unlimited = $query->get();

@bilalarshad21

You need to add css inside css/jquery.dataTables.css file:

.dataTables_filter input {
    width: 450px !important; 
}

@girliosalama95

Anyways, you can reset the $limit property:

$query = TestModel::where('a', 'b')->limit(100);
$query->limit = null;
$unlimited = $query->get();

@myszon

Could you try adding in your config/filesystems.php file a user_images key:

'user_images' => [
    'driver' => 'local',
    'root'   => public_path() . '/storage/',
],

After that, try in your code to access via useR_images by doing below:

Storage::allFiles('user_images');

Check more: https://laravel.com/docs/5.0/filesystem#basic-usage

@antoine_herbert

I am sorry about it.

But you will get many tutorials about curl. Check these to get the idea.

• https://stackoverflow.com/questions/48279382/curl-request-in-laravel
• https://laravelcode.com/post/laravel-55-how-to-make-curl-http-request-example

@bilalarshad21

You need to add css inside css/jquery.dataTables.css file:

.dataTables_filter input {
    width: 450px !important; 
}

@girliosalama95

I am wondering why are you using limits at first?

@sonukumar99

Yes you can query for model A and eager load the rest of the models:

$modelA->with(['modelB.modelD', 'modelC'])->get();

To make sure it works you need a relationship on model A for model B and model C, and a relationship on model B for model D.

@antoine_herbert

You might be following some unnecessary steps, to be honest. I am not sure what exactly is your business logic, but you may reduce some steps.

Calling the api endpoint directly is more meaningful to me, isn't that?

That's why I suggest you check the link. You may google it, you will find more tutorials about it. Check whichever you like.

@afoysal

I personally also tell you to follow @snapey 's verbose approach that is more organized and meaning.

@antoine_herbert

There are some issues in your code. Especially the way you defined your form action, that is not the correct way. Normally the laravel api is prefixed by api/ that you have missed in your action.

So, I recommend you to check this entry-level tutorial to understand how to use laravel and vue JS together.

https://www.itsolutionstuff.com/post/laravel-vue-js-axios-post-request-example-and-demoexample.html

@sukhchainsingh88

What if you try simply this?

...
->orderBy(DB::raw('CASE WHEN ...'))
...

@michaelritung89

Try useing vue-i18n:

$ npm install vue-i18n

Add it to you Vue app:

import Vue from 'vue'
import App from './App'
import router from './router'
import VueI18n from 'vue-i18n'
Vue.use(VueI18n)

Vue.config.productionTip = false

new Vue({
  el: '#app',
  router,
  template: '<App/>',
  components: { App }
})

Check more: https://kazupon.github.io/vue-i18n/

@rargyx

I think It is the problem of the name. Add name="bank_name" in select attribute and try:

               <div class="form-group mb-2">
                    <select class="form-control" name="bank_name">
                        <option value="" selected disabled>Select Bank</option>
                        <option value="bank1">BANK1</option>
                        <option value="bank2">BANK2</option>
                        <option value="bank3">BANK3</option>
                        <option value="bank4">BANK4</option>
                        <option value="bank5">BANK5</option>
                    </select>
                </div>

@su3158y

You should use whereHas instead of with to check child existence.

$customers = Customer::whereHas('items', function($query){
    return $query->where('status', 2);
})->get();

dd($customers);

I assume you already defined the proper relationship between Customer and Item.

@michaelritung89

Try useing vue-i18n:

$ npm install vue-i18n

Add it to you Vue app:

import Vue from 'vue'
import App from './App'
import router from './router'
import VueI18n from 'vue-i18n'
Vue.use(VueI18n)

Vue.config.productionTip = false

new Vue({
  el: '#app',
  router,
  template: '<App/>',
  components: { App }
})

Check more: https://kazupon.github.io/vue-i18n/

@sukhchainsingh88

What if you try simply this?

...
->orderBy(DB::raw('CASE WHEN ...'))
...

@rargyx

I think It is the problem of the name. Add name="bank_name" in select attribute and try:

               <div class="form-group mb-2">
                    <select class="form-control" name="bank_name">
                        <option value="" selected disabled>Select Bank</option>
                        <option value="bank1">BANK1</option>
                        <option value="bank2">BANK2</option>
                        <option value="bank3">BANK3</option>
                        <option value="bank4">BANK4</option>
                        <option value="bank5">BANK5</option>
                    </select>
                </div>

@sukhchainsingh88

Try asset('public/js/app.js'), and find a way to serve your site from the public, not from root.

asset('public/js/app.js')

@su3158y

You should use whereHas instead of with to check child existence.

$customers = Customer::whereHas('items', function($query){
    return $query->where('status', 2);
})->get();

dd($customers);

I assume you already defined the proper relationship between Customer and Item.

@sonukumar99

Yes you can query for model A and eager load the rest of the models:

$modelA->with(['modelB.modelD', 'modelC'])->get();

To make sure it works you need a relationship on model A for model B and model C, and a relationship on model B for model D.

@a4family

What if you try this?

$milestones = str_replace(array('[', ']', '"'),'',$milestones);

Since you try to remove square brackets and double-quotes.